JEE Main 2024 Physics question
A microwave of wavelength 2.0 cm falls normally on a slit of width 4.0 cm. The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5 m away from the slit, will be:
Answer: (C)
Solution
sin θ = λ/a = 1/2 ⇒ θ = 30°; angular spread = 2θ = 60°.