JEE Main 2024 Physics question
A transformer has an efficiency of 80% and works at 10 V and 4 kW. If the secondary voltage is 240 V, then the current in the secondary coil is:
Answer: (C)
Solution
Output power = 0.8 × 4000 = 3200 W; I = 3200/240 = 13.33 A.