JEE Main 2024 Physics question
Suppose a uniformly charged wall provides a uniform electric field of N/C normally. A charged particle of mass 2 g being suspended through a silk thread of length 20 cm and remain stayed at a distance of 10 cm from the wall. Then the charge on the particle will be μC where x = ……… . [Use g = 10 m/s]
Answer: 2
Solution
sin θ = 10/20 ⇒ tan θ = 1/√3. qE = mg tan θ gives q = (0.02/√3)/(2 × 10⁴) C = (1/√3) μC, so x = √3 ≈ 1.73, i.e. 2 to the
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