JEE Main 2024 Physics question
One end of a metal wire is fixed to a ceiling and a load of 2 kg hangs from the other end. A similar wire is attached to the bottom of the load and another load of 1 kg hangs from this lower wire. Then the ratio of longitudinal strain of upper wire to that of the lower wire will be . [Area of cross section of wire = 0.005 cm, Y = Nm and g = 10 ms]
Answer: 3
Solution
Strain = T/(AY): the upper wire carries 3 kg and the lower wire 1 kg, so the ratio is 3.