JEE Main 2024 Chemistry question
Consider the following redox reaction: MnO + H + HCO ⇌ Mn + HO + CO. The standard reduction potentials are given below (): = +1.51 V, = −0.49 V. If the equilibrium constant of the above reaction is given as , then the value of x = . (nearest integer)
Answer: 338
Solution
E°cell = 1.51 − (−0.49) = 2.00 V with n = 10 (2MnO₄⁻ + 5H₂C₂O₄); log K = nE°/0.0592 ≈ 338.