JEE Main 2024 Chemistry question
For a certain reaction at 300 K, K = 10, then ΔG° for the same reaction is – × kJ mol. (Given R = 8.314 JK mol)
Answer: 57
Solution
ΔG° = −2.303RT log K = −2.303 × 8.314 × 300 = −5743 J ≈ −57 × 10⁻¹ kJ mol⁻¹.
For a certain reaction at 300 K, K = 10, then ΔG° for the same reaction is – × kJ mol. (Given R = 8.314 JK mol)
ΔG° = −2.303RT log K = −2.303 × 8.314 × 300 = −5743 J ≈ −57 × 10⁻¹ kJ mol⁻¹.