JEE Main 2024 Chemistry question
The amount of electricity in Coulomb required for the oxidation of 1 mol of HO to O is × C.
Answer: 2
Solution
H₂O → ½O₂ + 2H⁺ + 2e⁻, so 2 F = 2 × 96500 ≈ 2 × 10⁵ C.
The amount of electricity in Coulomb required for the oxidation of 1 mol of HO to O is × C.
H₂O → ½O₂ + 2H⁺ + 2e⁻, so 2 F = 2 × 96500 ≈ 2 × 10⁵ C.