JEE Main 2024 Chemistry question
Mass of ethylene glycol (antifreeze) to be added to 18.6 kg of water to protect the freezing point at –24°C is kg (Molar mass in g mol for ethylene glycol 62, of water = 1.86 K kg mol)
Answer: 15
Solution
m = 24/1.86 = 12.9 mol kg⁻¹; moles = 12.9 × 18.6 = 240; mass = 240 × 62 g ≈ 14.9 kg ≈ 15 kg.