JEE Main 2024 Mathematics question
Consider the relations and defined as ⇔ a² + b² = 1 for all a, b ∈ R and (a, b) (c, d) ⇔ a + d = b + c for all (a, b), (c, d) ∈ N × N. Then:
Answer: (B)
Solution
R₁ is not reflexive (a² + a² ≠ 1 in general); R₂ is reflexive, symmetric and transitive.