JEE Main 2024 Physics question

PhysicsOscillationsJEE Main 2024

If R is the radius of the earth and the acceleration due to gravity on the surface of earth is g = π m/s, then the length of the second's pendulum at a height h = 2R from the surface of earth will be:

Answer: (C)

Solution

g′ = g/9; s ⇒ ℓ = g′/π² = 1/9 m.

Question ID VK-011233