JEE Main 2024 Physics question

PhysicsMotion in a Straight LineJEE Main 2024

A particle is moving in one dimension (along x-axis) under the action of a variable force. It's initial position was 16 m right of origin. The variation of its position (x) with time (t) is given as x = –3t + 18t + 16t, where x is in m and t is in s. The velocity of the particle when its acceleration becomes zero is m/s.

Answer: 52

Solution

a = −18t + 36 = 0 at t = 2 s; v = −9t² + 36t + 16 = 52 m/s.

Question ID VK-011241