JEE Main 2024 Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main 2024

The identical spheres each of mass 2M are placed at the corners of a right angled triangle with mutually perpendicular sides equal to 4 m each. Taking point of intersection of these two sides as origin, the magnitude of position vector of the centre of mass of the system is where the value of x is .

Answer: 3

Solution

Centre of mass = (4/3, 4/3), so |r| = 4√2/3.

Question ID VK-011244