JEE Main 2024 Mathematics question
The value of the integral equals:
Answer: (C)
Solution
x → π/4 − x leaves the integrand's denominator unchanged, so I = (π/8)∫₀^{π/4} dx/(sin⁴2x + cos⁴2x) = (π/8)(π/(2√2)) = √2π²/32.
The value of the integral equals:
x → π/4 − x leaves the integrand's denominator unchanged, so I = (π/8)∫₀^{π/4} dx/(sin⁴2x + cos⁴2x) = (π/8)(π/(2√2)) = √2π²/32.