JEE Main 2024 Mathematics question
Let y = y(x) be the solution of the differential equation , y(0) = 1. Then equals:
Answer: (C)
Solution
With u = x + y: du/dx = xu(2u² − 1). Put t = u²: ln[(2t − 1)/t] = x², so t = 1/(2 − ; at x = 1/√2, t = 1/(2 − √e).