JEE Main 2024 Chemistry question
The equilibrium constant for the reaction SO(g) ⇌ SO(g) + O(g) is = 4.9 × 10. The value of for the reaction given below is 2SO(g) + O(g) ⇌ 2SO(g) is
Answer: (D)
Solution
The new reaction is the reverse of the given one, doubled: K = (1/4.9 × 10⁻²)² ≈ 416.