JEE Main 2024 Physics question

Physics Motion in a Plane JEE Main 2024

The co-ordinates of a particle moving in x-y plane are given by: x = 2 + 4t, y = 3t + 8t. The motion of the particle is:

(A)non-uniformly accelerated.
(B)uniformly accelerated having motion along a straight line.
(C)uniform motion along a straight line.
(D)uniformly accelerated having motion along a parabolic path.Correct

Answer: (D)

Solution

= 0 and = 16 are constant, but the velocity (4, 3 + 16t) is not along the acceleration, so the path is a parabola.

Question ID VK-011416