JEE Main 2024 Chemistry question
The de-Broglie's wavelength of an electron in the 4th orbit is π. ( = Bohr's radius)
Answer: 8
Solution
λ = 2πr/n with r = 16a₀ and n = 4 gives 8πa₀.
The de-Broglie's wavelength of an electron in the 4th orbit is π. ( = Bohr's radius)
λ = 2πr/n with r = 16a₀ and n = 4 gives 8πa₀.