JEE Main 2024 Mathematics question
Let f : R → R be a function given by , where α, β ∈ R. If f is continuous at x = 0, then α² + β² is equal to-
Answer: (B)
Solution
Left limit = 2 = α; right limit = β/√2 = α ⇒ β = 2√2; α² + β² = 4 + 8 = 12.
Let f : R → R be a function given by , where α, β ∈ R. If f is continuous at x = 0, then α² + β² is equal to-
Left limit = 2 = α; right limit = β/√2 = α ⇒ β = 2√2; α² + β² = 4 + 8 = 12.