JEE Main 2024 Mathematics question
Let the solution y = y(x) of the differential equation satisfy y(π) = 1. Then is equal to .
Answer: 7
Solution
y = −1 − 2 sin x − 2 cos x + with C = 0 from y(π) = 1; y(π/2) = −3, so the value is 7.
Let the solution y = y(x) of the differential equation satisfy y(π) = 1. Then is equal to .
y = −1 − 2 sin x − 2 cos x + with C = 0 from y(π) = 1; y(π/2) = −3, so the value is 7.