JEE Main 2024 Physics question
In Young's double slit experiment, carried out with light of wavelength 5000Å, the distance between the slits is 0.3 mm and the screen is at 200 cm from the slits. The central maximum is at x = 0 cm. The value of x for third maxima is ............. mm.
Answer: 10
Solution
x = 3λD/d = 3 × 5 × 10⁻⁷ × 2/(0.3 × 10⁻³) = 10 mm.