JEE Main 2024 Physics question
Three capacitors of capacitances 25 μF, 30 μF and 45 μF are connected in parallel to a supply of 100 V. Energy stored in the above combination is E. When these capacitors are connected in series to the same supply, the stored energy is E. The value of x is………..
Answer: 86
Solution
Parallel: C = 100 μF, E = ½(100 μF)(100)² = 0.5 J. Series: 1/ = 1/25 + 1/30 +
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