JEE Main 2024 Chemistry question
The number of neutrons present in the more abundant isotope of boron is 'x'. Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is 'y'. The value of x + y is …
Answer: (D)
Solution
The more abundant isotope is ¹¹B, which has 6 neutrons; burning boron in air gives B₂O₃ with oxidation state +3: 6 + 3 = 9.