JEE Main 2024 Chemistry question
The value of Rydberg constant () is 2.18 × 10 J. The velocity of electron having mass 9.1 × 10 kg in Bohr's first orbit of hydrogen atom = ……… × 10 ms (nearest integer)
Answer: 22
Solution
½mv² = in the first orbit: v = √(2 × 2.18 × 10⁻¹⁸/9.1 × 10⁻³¹) = 2.19 × 10⁶ m s⁻¹ = 22 × 10⁵ m s⁻¹.