JEE Main 2024 Chemistry question
The heat of combustion of solid benzoic acid at constant volume is –321.30 kJ at 27°C. The heat of combustion at constant pressure is (–321.30 – xR) kJ, the value of x is …………….
Answer: 0.15
Solution
C₆H₅COOH(s) + 7½O₂ → 7CO₂ + 3H₂O(l): Δ = −½. ΔH = ΔU + Δ = −321.30 − ½R(300) =
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