JEE Main 2024 Chemistry question
An artificial cell is made by encapsulating 0.2 M glucose solution within a semipermeable memberane. The osmotic pressure developed when the artifical celll is placed within a 0.05 M solution of NaCl at 300 K is × 10 bar (Nearest Integer) [Given: R = 0.083 L bar mol K] Assume complete dissociation of NaCl
Answer: 25
Solution
Outside, NaCl gives 0.05 × 2 = 0.10 osmol L⁻¹, so the net osmotic pressure is (0.20 − 0.10) × 0.083 × 300 = 2.49 bar ≈ 25 × 10⁻¹ bar.