JEE Main 2024 Physics question
A series LCR circuit is subjected to an AC signal of 200 V, 50 Hz. If the voltage across the inductor (L = 10 mH) is 31.4 V, then the current in this circuit is :
Answer: (C)
Solution
= 2π(50)(0.01) = 3.14 Ω; I = 31.4/3.14 = 10 A.