JEE Main 2024 Physics question
A heavy box of mass 50 kg is moving on a horizontal surface. If co-efficient of kinetic friction between the box and horizontal surface is 0.3 then force of kinetic friction is:
Answer: (B)
Solution
f = μmg = 0.3 × 50 × 9.8 = 147 N (this needs g = 9.8 m/s², which the question does not state).