JEE Main 2024 Physics question
A hollow sphere is rolling on a plane surface about its axis of symmetry. The ratio of rotational kinetic energy to its total kinetic energy is . The value of x is .
Answer: 2
Solution
For a hollow sphere I = (2/3)MR²: = (1/2)(2/3)Mv² = Mv²/3 and = Mv²/2 + Mv²/3 = 5Mv²/6, so the ratio is 2/5.