JEE Main 2024 Physics question
The maximum height reached by a projectile is 64 m. If the initial velocity is halved, the new maximum height of the projectile is m.
Answer: 16
Solution
H ∝ u², so halving u gives H/4 = 16 m.
The maximum height reached by a projectile is 64 m. If the initial velocity is halved, the new maximum height of the projectile is m.
H ∝ u², so halving u gives H/4 = 16 m.