JEE Main 2024 Chemistry question

Combustion of 1 mole of benzene is expressed as CH(l) + O(g) → 6CO(g) + 3HO(l). The standard enthalpy of combustion of 2 mol of benzene is – 'x' kJ. x = . (1) Standard enthalpy of formation of 1 mol of CH(l), for the reaction 6C(graphite) + 3H(g) → CH(l) is 48.5 kJ mol. (2) Standard enthalpy of formation of 1 mol of CO(g), for the reaction C(graphite) + O(g) → CO(g) is –393.5 kJ mol. (3) Standard enthalpy of formation of 1 mol of HO(l), for the reaction H(g) + O(g) → HO(l) is –286 kJ mol.