JEE Main 2024 Chemistry question
X g of ethanamine was subjected to reaction with NaNO/HCl followed by hydrolysis to liberate N and HCl. The HCl generated was completely neutralised by 0.2 moles of NaOH. X is g.
Answer: 9
Solution
C₂H₅NH₂ + HNO₂ → C₂H₅OH + N₂ + H₂O releases one HCl per amine, so 0.2 mol amine × 45 g mol⁻¹ = 9 g.