JEE Main 2024 Chemistry question
In the Claisen-Schmidt reaction to prepare 351 g of dibenzalacetone using 87 g of acetone, the amount of benzaldehyde required is g. (Nearest integer)
Answer: 318
Solution
Dibenzalacetone (234 g mol⁻¹): 351 g = 1.5 mol, which needs 1.5 mol acetone (87 g) and 3 mol benzaldehyde = 3 × 106 = 318 g.