JEE Main 2024 Mathematics question
Let A(−1, 1) and B(2, 3) be two points and P be a variable point above the line AB such that the area of ΔPAB is 10. If the locus of P is ax + by = 15, then 5a + 2b is:
Answer: (A)
Solution
AB: 2x − 3y + 5 = 0 with |AB| = √13, so the distance of P from AB is 20/√13. Above the line, −2x + 3y − 5 =
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