JEE Main 2024 Physics question
To find the spring constant (k) of a spring experimentally, a student commits 2% positive error in the measurement of time and 1% negative error in measurement of mass. The percentage error in determining value of k is:
Answer: (D)
Solution
k = 4π²m/T², so Δk/k = Δm/m + 2ΔT/T = 1% + 4% = 5%.