JEE Main 2024 Physics question
A particle is doing simple harmonic motion of amplitude 0.06 m and time period 3.14 s. The maximum velocity of the particle is cm/s.
Answer: 12
Solution
ω = 2π/3.14 = 2 rad/s, so = Aω = 0.06 × 2 = 0.12 m/s = 12 cm/s.