JEE Main 2024 Mathematics question
If , then
Answer: (B)
Solution
For x ≠ 0, f″(x) = 6x sin(1/x) − 4cos(1/x) − sin(1/x)/x, so f″(2/π) = (12/π)(1) − 0 − π/2 = (24 − π²)/2π. At 0, f′(0) = 0 but f′(x) = 3x²
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