JEE Main 2024 Mathematics question
Let the relations R₁ and R₂ on the set X = {1, 2, 3, ..., 20} be given by R₁ = {(x, y) : 2x − 3y = 2} and R₂ = {(x, y) : −5x + 4y = 0}. If M and N be the minimum number of elements required to be added in R₁ and R₂, respectively, in order to make the relations symmetric, then M + N equals
Answer: (D)
Solution
R₁ = {(4,2), (7,4), (10,6), (13,8), (16,10), (19,12)} has 6 pairs whose reverses
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