JEE Main 2024 Mathematics question
Let y = y(x) be the solution of the differential equation , y(1) = 0. Then y(0) is
Answer: (B)
Solution
The integrating factor is : y = /2 + C, and y(1) = 0 gives C = −/2. At x = 0, y = (1 − /2.
Let y = y(x) be the solution of the differential equation , y(1) = 0. Then y(0) is
The integrating factor is : y = /2 + C, and y(1) = 0 gives C = −/2. At x = 0, y = (1 − /2.