JEE Main 2024 Mathematics question
Let y = y(x) be the solution of the differential equation , x > 0 and y(e⁻¹) = 0. Then, y(e) is equal to
Answer: (C)
Solution
Dividing by 2x ln x gives y′ + y/(x ln x) = 3/(2x²); the integrating factor is ln x, so y ln x = ∫(3 ln
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