JEE Main 2024 Mathematics question
If the second, third and fourth terms in the expansion of (x + y)ⁿ are 135, 30 and , respectively, then 6(n³ + x² + y) is equal to .
Answer: 806
Solution
T₃/T₂ = ((n − 1)/2)(y/x) = 2/9 and T₄/T₃ = ((n − 2)/3)(y/x) = 1/9 give n = 5
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