JEE Main 2020 Physics question

When photon of energy 4.0 eV strikes the surface of a metal A, the ejected photoelectrons have maximum kinetic energy eV and de-Broglie wavelength . The maximum kinetic energy of photoelectrons liberated from another metal B by photon of energy 4.50 eV is eV. If the de-Broglie wavelength of these photoelectrons , then the work function of metal B is :

• (A)2 eV
• (B)4 eVCorrect
• (C)1.5 eV
• (D)3 eV