JEE Main 2020 Physics question
A body A, of mass m = 0.1 kg has an initial velocity of . It collides elastically with another body, B of the same mass which has an initial velocity of . After collision, A moves with a velocity . The energy of B after collision is written as J. The value of x is .
Answer: 1
Solution
Energy conservation: 0.5·0.1·(9+25) = 0.5·0.1·32 + gives = 0.1 J, so x = 1 (the paper flags "Answer not match").