JEE Main 2020 Chemistry question
The volume (in mL) of 0.125 M required to quantitatively precipitate chloride ions in 0.3 g of is –––––– = 267.46 g/mol = 169.87 g/mol
Answer: 26.92
The volume (in mL) of 0.125 M required to quantitatively precipitate chloride ions in 0.3 g of is –––––– = 267.46 g/mol = 169.87 g/mol