JEE Main 2024 Physics question
In finding out refractive index of glass slab the following observations were made through travelling microscope: 50 vernier scale division = 49 MSD; 20 divisions on main scale in each cm. For mark on paper MSR = 8.45 cm, VC = 26. For mark on paper seen through slab MSR = 7.12 cm, VC = 41. For powder particle on the top surface of the glass slab MSR = 4.05 cm, VC = 1. (MSR = Main Scale Reading, VC = Vernier Coincidence). Refractive index of the glass slab is:
Answer: (A)
Solution
1 MSD = 0.05 cm and the least count is 0.05/50 = 0.001 cm. Readings: 8.476, 7.161 and
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