JEE Main 2024 Physics question

PhysicsSemiconductor ElectronicsJEE Main 2024

Not in JEE Advanced syllabus

The acceptor level of a p-type semiconductor is 6 eV. The maximum wavelength of light which can create a hole would be: Given hc = 1242 eV nm.

Answer: (C)

Solution

λ = hc/E = 1242/6 = 207 nm.

Question ID VK-012063