JEE Main 2024 Physics question
Pressure inside a soap bubble is greater than the pressure outside by an amount: (given: R = Radius of bubble, S = Surface tension of bubble)
Answer: (A)
Solution
A soap bubble has two surfaces, so ΔP = 4S/R.
Pressure inside a soap bubble is greater than the pressure outside by an amount: (given: R = Radius of bubble, S = Surface tension of bubble)
A soap bubble has two surfaces, so ΔP = 4S/R.