JEE Main 2024 Physics question
A body projected vertically upwards with a certain speed from the top of a tower reaches the ground in t₁. If it is projected vertically downwards from the same point with the same speed, it reaches the ground in t₂. Time required to reach the ground, if it is dropped from the top of the tower, is:
Answer: (A)
Solution
−h = ut₁ − ½gt₁² and −h = −ut₂ − ½gt₂². Eliminating u gives h = ½g·t₁t₂, so the drop time is √(2h/g) = √(t₁t₂).