JEE Main 2024 Physics question

PhysicsAtomsJEE Main 2024

In Franck-Hertz experiment, the first dip in the current-voltage graph for hydrogen is observed at 10.2 V. The wavelength of light emitted by hydrogen atom when excited to the first excitation level is nm. (Given hc = 1245 eV nm, e = 1.6 × 10⁻¹⁹ C).

Answer: 122

Solution

λ = hc/E = 1245/10.2 ≈ 122 nm.

Question ID VK-012078