JEE Main 2024 Physics question
For a given series LCR circuit it is found that maximum current is drawn when value of variable capacitance is 2.5 nF. If resistance of 200 Ω and 100 mH inductor is being used in the given circuit. The frequency of ac source is × 10³ Hz. (given π² = 10)
Answer: 10
Solution
At resonance f² = 1/(4π²LC) = 1/(40 × 0.1 × 2.5 × 10⁻⁹) = 10⁸, so f = 10⁴ Hz = 10 × 10³ Hz.