JEE Main 2024 Physics question
A particle moves in a straight line so that its displacement x at any time t is given by x² = 1 + t². Its acceleration at any time t is x⁻ⁿ where n = .
Answer: 3
Solution
v = t/x and a = (x − tv)/x² = (x² − t²)/x³ = 1/x³.